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Grade 12 · Mathematics · Unit 10–11

Trigonometry

Drag diagrams, type your own values, and see every step of the working.

Trigonometric Ratios

θadjopphyp
Refer to the diagram above, for a right-angled triangle with angle θ\theta:
sin⁡θ=opphypcos⁡θ=adjhyptan⁡θ=oppadj\sin\theta = \frac{\text{opp}}{\text{hyp}} \qquad \cos\theta = \frac{\text{adj}}{\text{hyp}} \qquad \tan\theta = \frac{\text{opp}}{\text{adj}}
💡 Memory trick: SOH CAH TOA
Theorem 1📌 Learn for exam
Unit Circle definition

Refer to the diagram below. On a unit circle (radius = 1), for any angle θ\theta measured from the positive x-axis:

cos⁡θ=x-coordinate of Psin⁡θ=y-coordinate of P\cos\theta = x\text{-coordinate of }P \qquad \sin\theta = y\text{-coordinate of }P
(x,y)=(cos⁡θ,sin⁡θ)(x, y) = (\cos \theta, \sin \theta)
tan⁡θ=sin⁡θcos⁡θ=yx(x=cos⁡θ≠0)\tan\theta = \frac{\sin\theta}{\cos\theta} = \frac{y}{x} \qquad (x = \cos\theta \neq 0)
▸ Unit Circle — drag P around the circlethe point P is draggable
Loading diagram…
Special angles — memorise these:
θsin⁡θcos⁡θtan⁡θ0°01030°12321345°2222160°3212390°10undef\begin{array}{c|ccc} \theta & \sin\theta & \cos\theta & \tan\theta \\ \hline 0° & 0 & 1 & 0 \\ 30° & \frac{1}{2} & \frac{\sqrt{3}}{2} & \frac{1}{\sqrt{3}} \\ 45° & \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 1 \\ 60° & \frac{\sqrt{3}}{2} & \frac{1}{2} & \sqrt{3} \\ 90° & 1 & 0 & \text{undef} \end{array}
Tip
The unit circle definition works for all angles — not just angles in right-angled triangles. That is why we need it for Grade 12.
Worked Example

Special angle exact value

Without a calculator, find the exact value of sin⁡30°⋅cos⁡60°+cos⁡30°⋅sin⁡60°\sin 30° \cdot \cos 60° + \cos 30° \cdot \sin 60°.